Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx, yyy and zzz.{−2x+3y−5z=12−x−y+2z=−12−4x+y=−16\begin{cases} - 2 x + 3 y - 5 z = 12 \\ - x - y + 2 z = -12 \\ - 4 x + y = -16 \end{cases}⎩⎨⎧−2x+3y−5z=12−x−y+2z=−12−4x+y=−16 Show answer Walk through it step by step Practice more like this Review this concept