Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx, yyy and zzz.{−3x−y−4z=−35−3x−4y+5z=1y−2z=−7\begin{cases} - 3 x - y - 4 z = -35 \\ - 3 x - 4 y + 5 z = 1 \\ y - 2 z = -7 \end{cases}⎩⎨⎧−3x−y−4z=−35−3x−4y+5z=1y−2z=−7 Show answer Walk through it step by step Practice more like this Review this concept