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Algebra 2HardSystems of Equations

Systems of Equations · Hard problem

Solve the system for xx, yy and zz.

{3x+2z=16−2x−4z=−244x+2y+4z=20\begin{cases} 3 x + 2 z = 16 \\ - 2 x - 4 z = -24 \\ 4 x + 2 y + 4 z = 20 \end{cases}