Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx, yyy and zzz.{3x+2z=16−2x−4z=−244x+2y+4z=20\begin{cases} 3 x + 2 z = 16 \\ - 2 x - 4 z = -24 \\ 4 x + 2 y + 4 z = 20 \end{cases}⎩⎨⎧3x+2z=16−2x−4z=−244x+2y+4z=20 Show answer Walk through it step by step Practice more like this Review this concept