Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx, yyy and zzz.{−4x−3y−2z=−225x−5y+z=1−2x−4z=−26\begin{cases} - 4 x - 3 y - 2 z = -22 \\ 5 x - 5 y + z = 1 \\ - 2 x - 4 z = -26 \end{cases}⎩⎨⎧−4x−3y−2z=−225x−5y+z=1−2x−4z=−26 Show answer Walk through it step by step Practice more like this Review this concept