Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx, yyy and zzz.{3x+3y+5z=−113x+2y+4z=−102x−4y−4z=4\begin{cases} 3 x + 3 y + 5 z = -11 \\ 3 x + 2 y + 4 z = -10 \\ 2 x - 4 y - 4 z = 4 \end{cases}⎩⎨⎧3x+3y+5z=−113x+2y+4z=−102x−4y−4z=4 Show answer Walk through it step by step Practice more like this Review this concept