Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx, yyy and zzz.{−3y+z=−15−2x−5y+2z=−14−4x−5y+5z=5\begin{cases} - 3 y + z = -15 \\ - 2 x - 5 y + 2 z = -14 \\ - 4 x - 5 y + 5 z = 5 \end{cases}⎩⎨⎧−3y+z=−15−2x−5y+2z=−14−4x−5y+5z=5 Show answer Walk through it step by step Practice more like this Review this concept