Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx, yyy and zzz.{y+4z=14−5x−y−2z=−31−5x+4y+5z=−13\begin{cases} y + 4 z = 14 \\ - 5 x - y - 2 z = -31 \\ - 5 x + 4 y + 5 z = -13 \end{cases}⎩⎨⎧y+4z=14−5x−y−2z=−31−5x+4y+5z=−13 Show answer Walk through it step by step Practice more like this Review this concept