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Algebra 2HardSystems of Equations

Systems of Equations · Hard problem

Solve the system for xx, yy and zz.

{y+4z=14−5x−y−2z=−31−5x+4y+5z=−13\begin{cases} y + 4 z = 14 \\ - 5 x - y - 2 z = -31 \\ - 5 x + 4 y + 5 z = -13 \end{cases}