Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx, yyy and zzz.{−2z=03x+4y+5z=−83x−5y−5z=−17\begin{cases} - 2 z = 0 \\ 3 x + 4 y + 5 z = -8 \\ 3 x - 5 y - 5 z = -17 \end{cases}⎩⎨⎧−2z=03x+4y+5z=−83x−5y−5z=−17 Show answer Walk through it step by step Practice more like this Review this concept