Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx, yyy and zzz.{3x+2y−4z=252x+2y+z=−5−4x+5y−5z=−20\begin{cases} 3 x + 2 y - 4 z = 25 \\ 2 x + 2 y + z = -5 \\ - 4 x + 5 y - 5 z = -20 \end{cases}⎩⎨⎧3x+2y−4z=252x+2y+z=−5−4x+5y−5z=−20 Show answer Walk through it step by step Practice more like this Review this concept