Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx, yyy and zzz.{−5x+3y=−5−x+4y−2z=−282x+3z=11\begin{cases} - 5 x + 3 y = -5 \\ - x + 4 y - 2 z = -28 \\ 2 x + 3 z = 11 \end{cases}⎩⎨⎧−5x+3y=−5−x+4y−2z=−282x+3z=11 Show answer Walk through it step by step Practice more like this Review this concept