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Algebra 2HardSystems of Equations

Systems of Equations · Hard problem

Solve the system for xx, yy and zz.

{−5x+3y=−5−x+4y−2z=−282x+3z=11\begin{cases} - 5 x + 3 y = -5 \\ - x + 4 y - 2 z = -28 \\ 2 x + 3 z = 11 \end{cases}