Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx, yyy and zzz.{−3x+3z=−36−4x−3y=−12−2x−3y−5z=30\begin{cases} - 3 x + 3 z = -36 \\ - 4 x - 3 y = -12 \\ - 2 x - 3 y - 5 z = 30 \end{cases}⎩⎨⎧−3x+3z=−36−4x−3y=−12−2x−3y−5z=30 Show answer Walk through it step by step Practice more like this Review this concept