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Algebra 2HardSystems of Equations

Systems of Equations · Hard problem

Solve the system for xx, yy and zz.

{3x−3z=125x+3z=−20−3x−2y+z=−8\begin{cases} 3 x - 3 z = 12 \\ 5 x + 3 z = -20 \\ - 3 x - 2 y + z = -8 \end{cases}