Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx, yyy and zzz.{3x−3z=125x+3z=−20−3x−2y+z=−8\begin{cases} 3 x - 3 z = 12 \\ 5 x + 3 z = -20 \\ - 3 x - 2 y + z = -8 \end{cases}⎩⎨⎧3x−3z=125x+3z=−20−3x−2y+z=−8 Show answer Walk through it step by step Practice more like this Review this concept