Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx, yyy and zzz.{−2y+2z=0−5x−3y−4z=−4−3x+3y−z=10\begin{cases} - 2 y + 2 z = 0 \\ - 5 x - 3 y - 4 z = -4 \\ - 3 x + 3 y - z = 10 \end{cases}⎩⎨⎧−2y+2z=0−5x−3y−4z=−4−3x+3y−z=10 Show answer Walk through it step by step Practice more like this Review this concept