Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx, yyy and zzz.{3x+4y+4z=29−4y+z=53x−4y−4z=−11\begin{cases} 3 x + 4 y + 4 z = 29 \\ - 4 y + z = 5 \\ 3 x - 4 y - 4 z = -11 \end{cases}⎩⎨⎧3x+4y+4z=29−4y+z=53x−4y−4z=−11 Show answer Walk through it step by step Practice more like this Review this concept