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Algebra 2HardSystems of Equations

Systems of Equations · Hard problem

Solve the system for xx, yy and zz.

{3x+5y+4z=242x+4y+3z=213x−5y+5z=−33\begin{cases} 3 x + 5 y + 4 z = 24 \\ 2 x + 4 y + 3 z = 21 \\ 3 x - 5 y + 5 z = -33 \end{cases}