Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx, yyy and zzz.{3x+5y+4z=242x+4y+3z=213x−5y+5z=−33\begin{cases} 3 x + 5 y + 4 z = 24 \\ 2 x + 4 y + 3 z = 21 \\ 3 x - 5 y + 5 z = -33 \end{cases}⎩⎨⎧3x+5y+4z=242x+4y+3z=213x−5y+5z=−33 Show answer Walk through it step by step Practice more like this Review this concept