Algebra 2HardSystems of Equations ShareSystems of Equations · Hard problemSolve the system for xxx, yyy and zzz.{4y+2z=14−2x−y+5z=−32−3x+2y−2z=−2\begin{cases} 4 y + 2 z = 14 \\ - 2 x - y + 5 z = -32 \\ - 3 x + 2 y - 2 z = -2 \end{cases}⎩⎨⎧4y+2z=14−2x−y+5z=−32−3x+2y−2z=−2 Show answer Walk through it step by step Practice more like this Review this concept