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Algebra 2HardSystems of Equations

Systems of Equations · Hard problem

Solve the system for xx, yy and zz.

{−2x−5y−z=23−5x−y+3z=113x+y=−5\begin{cases} - 2 x - 5 y - z = 23 \\ - 5 x - y + 3 z = 11 \\ 3 x + y = -5 \end{cases}