StatisticsMediumRandom Variables ShareRandom Variables · Medium problemA random variable XXX has P(X=0)=23P(X = 0) = \dfrac{2}{3}P(X=0)=32, P(X=5)=16P(X = 5) = \dfrac{1}{6}P(X=5)=61, P(X=6)=16P(X = 6) = \dfrac{1}{6}P(X=6)=61. Find E[X]E[X]E[X]. Express your answer as a common fraction or decimal.Check Show answer Walk through it step by step Practice more like this Review this concept