StatisticsMediumRandom Variables ShareRandom Variables · Medium problemA random variable XXX has P(X=2)=13P(X = 2) = \dfrac{1}{3}P(X=2)=31, P(X=3)=13P(X = 3) = \dfrac{1}{3}P(X=3)=31, P(X=6)=13P(X = 6) = \dfrac{1}{3}P(X=6)=31. Find E[X]E[X]E[X]. Express your answer as a common fraction or decimal.Check Show answer Walk through it step by step Practice more like this Review this concept