StatisticsHardRandom Variables ShareRandom Variables · Hard problemA random variable XXX has P(X=0)=14P(X = 0) = \dfrac{1}{4}P(X=0)=41, P(X=5)=14P(X = 5) = \dfrac{1}{4}P(X=5)=41, P(X=7)=12P(X = 7) = \dfrac{1}{2}P(X=7)=21. Find Var(X)\operatorname{Var}(X)Var(X). Express your answer as a common fraction or decimal.Check Show answer Walk through it step by step Practice more like this Review this concept