StatisticsHardRandom Variables ShareRandom Variables · Hard problemA random variable XXX has P(X=4)=19P(X = 4) = \dfrac{1}{9}P(X=4)=91, P(X=5)=49P(X = 5) = \dfrac{4}{9}P(X=5)=94, P(X=7)=49P(X = 7) = \dfrac{4}{9}P(X=7)=94. Find Var(X)\operatorname{Var}(X)Var(X). Express your answer as a common fraction or decimal.Check Show answer Walk through it step by step Practice more like this Review this concept