StatisticsMediumRandom Variables ShareRandom Variables · Medium problemA random variable XXX has P(X=0)=35P(X = 0) = \dfrac{3}{5}P(X=0)=53, P(X=2)=15P(X = 2) = \dfrac{1}{5}P(X=2)=51, P(X=5)=15P(X = 5) = \dfrac{1}{5}P(X=5)=51. Find E[X]E[X]E[X]. Express your answer as a common fraction or decimal.Check Show answer Walk through it step by step Practice more like this Review this concept