StatisticsHardRandom Variables ShareRandom Variables · Hard problemA random variable XXX has P(X=2)=13P(X = 2) = \dfrac{1}{3}P(X=2)=31, P(X=5)=16P(X = 5) = \dfrac{1}{6}P(X=5)=61, P(X=6)=12P(X = 6) = \dfrac{1}{2}P(X=6)=21. Find Var(X)\operatorname{Var}(X)Var(X). Express your answer as a common fraction or decimal.Check Show answer Walk through it step by step Practice more like this Review this concept