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StatisticsMediumRandom Variables

Random Variables · Medium problem

A random variable XX has P(X=1)=14P(X = 1) = \dfrac{1}{4}, P(X=4)=12P(X = 4) = \dfrac{1}{2}, P(X=6)=14P(X = 6) = \dfrac{1}{4}. Find E[X]E[X]. Express your answer as a common fraction or decimal.