StatisticsMediumRandom Variables ShareRandom Variables · Medium problemA random variable XXX has P(X=1)=14P(X = 1) = \dfrac{1}{4}P(X=1)=41, P(X=4)=12P(X = 4) = \dfrac{1}{2}P(X=4)=21, P(X=6)=14P(X = 6) = \dfrac{1}{4}P(X=6)=41. Find E[X]E[X]E[X]. Express your answer as a common fraction or decimal.Check Show answer Walk through it step by step Practice more like this Review this concept