StatisticsHardRandom Variables ShareRandom Variables · Hard problemFor the distribution P(X=0)=0.35P(X = 0) = 0.35P(X=0)=0.35, P(X=1)=0.10P(X = 1) = 0.10P(X=1)=0.10, P(X=2)=0.15P(X = 2) = 0.15P(X=2)=0.15, P(X=3)=0.40P(X = 3) = 0.40P(X=3)=0.40, how do the mean, median and mode compare?Amode <<< median <<< meanBmedian <<< mean <<< modeCmean === median <<< modeDmean <<< median <<< modeCheck Show answer Walk through it step by step Practice more like this Review this concept