Confidence Intervals · Medium problem

There is a $95\%$ probability that the true proportion lies in $(0.471, 0.569)$

$95\%$ of voters have opinions between $47.1\%$ and $56.9\%$

If we repeated the poll many times, about $95\%$ of the intervals made this way would contain the true proportion

$95\%$ of future polls of this size will give a proportion between $0.471$ and $0.569$