Confidence Intervals · Challenge problem

From a sample of $n = 10$, a $90\%$ $t$ interval for a mean is $(46.71, 53.29)$. Find the upper end of the $95\%$ interval from the same data. Use $t^* = 1.833$ ($90\%$) and $t^* = 2.262$ ($95\%$), both with $9$ degrees of freedom. Give your answer to the nearest hundredth.