Proof WritingChallengeWriting It Up ShareWriting It Up · Challenge problemA draft says: "a∣bca \mid bca∣bc and a∤ba \nmid ba∤b, so a∣ca \mid ca∣c." Which extra hypothesis makes this step valid?Aa<ba < ba<bBgcd(a,b)=1\gcd(a, b) = 1gcd(a,b)=1Caaa is oddDbbb is primeCheck Show answer Walk through it step by step Practice more like this Review this concept