Proof WritingHardInduction ShareInduction · Hard problemTo prove 7∣32n−2n7 \mid 3^{2n} - 2^n7∣32n−2n for all n≥0n \ge 0n≥0, the step writes 32k+2−2k+1=9(32k−2k)+c⋅2k3^{2k+2} - 2^{k+1} = 9(3^{2k} - 2^k) + c\cdot2^k32k+2−2k+1=9(32k−2k)+c⋅2k. What is ccc?Check Show answer Walk through it step by step Practice more like this Review this concept