Number TheoryMediumModular Arithmetic ShareModular Arithmetic · Medium problemSuppose a≡b(mod12)a \equiv b \pmod{12}a≡b(mod12), where aaa and bbb are positive integers. Which statement MUST be true?Aa3−b3a^3 - b^3a3−b3 is divisible by 121212B2a≡2b(mod12)2^a \equiv 2^b \pmod{12}2a≡2b(mod12)Ca≡b(mod24)a \equiv b \pmod{24}a≡b(mod24)Da+b≡0(mod12)a + b \equiv 0 \pmod{12}a+b≡0(mod12)EIf a,ba, ba,b are even, a2≡b2(mod12)\dfrac a2 \equiv \dfrac b2 \pmod{12}2a≡2b(mod12)Check Show answer Walk through it step by step Practice more like this Review this concept