Number TheoryMediumHard Number Theory ShareHard Number Theory · Medium problemEvaluate ∑k=112⌊5k13⌋\displaystyle\sum_{k=1}^{12}\left\lfloor \frac{5k}{13} \right\rfloork=1∑12⌊135k⌋.Check Show answer Walk through it step by step Practice more like this Review this concept