Number TheoryMediumThe Chinese Remainder Theorem ShareThe Chinese Remainder Theorem · Medium problemWhich system has no solution?Ax≡1(mod4), x≡3(mod6)x \equiv 1 \pmod 4,\ x \equiv 3 \pmod 6x≡1(mod4), x≡3(mod6)Bx≡1(mod4), x≡2(mod6)x \equiv 1 \pmod 4,\ x \equiv 2 \pmod 6x≡1(mod4), x≡2(mod6)Cx≡2(mod9), x≡5(mod12)x \equiv 2 \pmod 9,\ x \equiv 5 \pmod{12}x≡2(mod9), x≡5(mod12)Dx≡0(mod8), x≡4(mod12)x \equiv 0 \pmod 8,\ x \equiv 4 \pmod{12}x≡0(mod8), x≡4(mod12)Check Show answer Walk through it step by step Practice more like this Review this concept