PutnamSuperchallengeIntegrals I: Feynman's Trick ShareIntegrals I: Feynman's Trick · Superchallenge problemEvaluate ∫01x8−1lnx dx\displaystyle\int_0^1 \frac{x^{8} - 1}{\ln x}\,dx∫01lnxx8−1dx.Check Show answer Walk through it step by step Practice more like this Review this concept