PrecalculusHardSystems, Matrices, and Determinants ShareSystems, Matrices, and Determinants · Hard problemUsing that inverse, solve {x=32x+y=43x+4y+z=5\begin{cases} x=3 \\ 2x+y=4 \\ 3x+4y+z=5 \end{cases}⎩⎨⎧x=32x+y=43x+4y+z=5A(3,+2,4)(3,+2,4)(3,+2,4)B(3,−2,5)(3,-2,5)(3,−2,5)C(6,−2,4)(6,-2,4)(6,−2,4)D(3,−2,4)(3,-2,4)(3,−2,4)Check Show answer Walk through it step by step Practice more like this Review this concept