PrecalculusChallengeSystems, Matrices, and Determinants ShareSystems, Matrices, and Determinants · Challenge problem{x+y+z=2x2+y2+z2=6x3+y3+z3=8\begin{cases} x+y+z=2 \\ x^2+y^2+z^2=6 \\ x^3+y^3+z^3=8 \end{cases}⎩⎨⎧x+y+z=2x2+y2+z2=6x3+y3+z3=8 (find {x,y,z}\{x,y,z\}{x,y,z}).A{−2,1,2}\{-2,1,2\}{−2,1,2}B−{−1,1,2}-\{-1,1,2\}−{−1,1,2}C{−1,1,2}\{-1,1,2\}{−1,1,2}D{−1,1,3}\{-1,1,3\}{−1,1,3}Check Show answer Walk through it step by step Practice more like this Review this concept