PrecalculusSuperchallengeSystems, Matrices, and Determinants ShareSystems, Matrices, and Determinants · Superchallenge problem{x+y+z=3xy+yz+zx=−1xyz=−3\begin{cases} x+y+z=3 \\ xy+yz+zx=-1 \\ xyz=-3 \end{cases}⎩⎨⎧x+y+z=3xy+yz+zx=−1xyz=−3 (list the solution set).A{−1,1,4}\{-1,1,4\}{−1,1,4}B{−1,1,3}\{-1,1,3\}{−1,1,3}C{−2,1,3}\{-2,1,3\}{−2,1,3}D−{−1,1,3}-\{-1,1,3\}−{−1,1,3}Check Show answer Walk through it step by step Practice more like this Review this concept