PrecalculusChallengeSystems, Matrices, and Determinants ShareSystems, Matrices, and Determinants · Challenge problemSolve by Cramer's Rule: {x+y+z=62x−y+z=6x+2y−z=1\begin{cases} x+y+z=6 \\ 2x-y+z=6 \\ x+2y-z=1 \end{cases}⎩⎨⎧x+y+z=62x−y+z=6x+2y−z=1A(1,2,3)(1, 2, 3)(1,2,3)B(−2,1,3)(-2, 1, 3)(−2,1,3)C(2,1,3)(2,1,3)(2,1,3)D(2,−1,3)(2, -1, 3)(2,−1,3)Check Show answer Walk through it step by step Practice more like this Review this concept