PrecalculusHard SharePrecalculus · Hard problemSolve 3cosx+sinx=1\sqrt3\cos x+\sin x=13cosx+sinx=1 on [0,2π)[0,2\pi)[0,2π).A2π, 11π6\dfrac{2}{\pi},\ \dfrac{11\pi}{6}π2, 611πBπ4, 11π6\dfrac{\pi}{4},\ \dfrac{11\pi}{6}4π, 611πCπ2, 11π7\dfrac{\pi}{2},\ \dfrac{11\pi}{7}2π, 711πDπ2, 11π6\dfrac{\pi}{2},\ \dfrac{11\pi}{6}2π, 611πCheck Show answer Walk through it step by step Practice more like this