MathCastle
PrecalculusMedium

Precalculus · Medium problem

Use tan⁡θ2=1−cos⁡θsin⁡θ\tan\dfrac{\theta}{2}=\dfrac{1-\cos\theta}{\sin\theta} with θ=π6\theta=\dfrac{\pi}{6} to find tan⁡π12\tan\dfrac{\pi}{12}.

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