PrecalculusMedium SharePrecalculus · Medium problemUse tanθ2=1−cosθsinθ\tan\dfrac{\theta}{2}=\dfrac{1-\cos\theta}{\sin\theta}tan2θ=sinθ1−cosθ with θ=π6\theta=\dfrac{\pi}{6}θ=6π to find tanπ12\tan\dfrac{\pi}{12}tan12π.Check Show answer Walk through it step by step Practice more like this