PrecalculusMedium SharePrecalculus · Medium problemSolve cosx−sinx=1\cos x-\sin x=1cosx−sinx=1 on [0,2π)[0,2\pi)[0,2π) by squaring, and check for extraneous solutions.Ax=0, 3π3x=0,\ \dfrac{3\pi}{3}x=0, 33πBx=0, 23πx=0,\ \dfrac{2}{3\pi}x=0, 3π2Cx=0, 3π2x=0,\ \dfrac{3\pi}{2}x=0, 23πDx=0, 3π1x=0,\ \dfrac{3\pi}{1}x=0, 13πCheck Show answer Walk through it step by step Practice more like this