PrecalculusChallengeAnalytic Trigonometry ShareAnalytic Trigonometry · Challenge problemSolve sin2x+sin22x+sin23x=32\sin^2 x+\sin^2 2x+\sin^2 3x=\dfrac{3}{2}sin2x+sin22x+sin23x=23.Aπ3+πn, 2π4+πn\dfrac{\pi}{3}+\pi n,\ \dfrac{2\pi}{4}+\pi n3π+πn, 42π+πnB3π+πn, 2π3+πn\dfrac{3}{\pi}+\pi n,\ \dfrac{2\pi}{3}+\pi nπ3+πn, 32π+πnCπ3−πn, 2π3+πn\dfrac{\pi}{3}-\pi n,\ \dfrac{2\pi}{3}+\pi n3π−πn, 32π+πnDπ3+πn, 2π3+πn\dfrac{\pi}{3}+\pi n,\ \dfrac{2\pi}{3}+\pi n3π+πn, 32π+πnCheck Show answer Walk through it step by step Practice more like this Review this concept