PrecalculusChallengeAnalytic Trigonometry ShareAnalytic Trigonometry · Challenge problemSolve sin3xcos3x+cos3xsin3x=34\sin^3 x\cos3x+\cos^3 x\sin3x=\dfrac{3}{4}sin3xcos3x+cos3xsin3x=43.Aπ8+πn3\dfrac{\pi}{8}+\dfrac{\pi n}{3}8π+3πnBπ8+πn2\dfrac{\pi}{8}+\dfrac{\pi n}{2}8π+2πnC8π+πn2\dfrac{8}{\pi}+\dfrac{\pi n}{2}π8+2πnDπ8−πn2\dfrac{\pi}{8}-\dfrac{\pi n}{2}8π−2πnCheck Show answer Walk through it step by step Practice more like this Review this concept