PrecalculusEasy SharePrecalculus · Easy problemGiven sinθ=513\sin\theta=\dfrac{5}{13}sinθ=135 with θ\thetaθ in Quadrant I, use sin2θ+cos2θ=1\sin^2\theta+\cos^2\theta=1sin2θ+cos2θ=1 to find cosθ\cos\thetacosθ.Check Show answer Walk through it step by step Practice more like this