PrecalculusMediumExponential and Logarithmic Functions ShareExponential and Logarithmic Functions · Medium problemRewrite y=2xy=2^{x}y=2x in the natural-base form y=ekxy=e^{kx}y=ekx, giving kkk exactly.Ay=e(ln4)xy=e^{(\ln 4)x}y=e(ln4)xBy=e(ln1)xy=e^{(\ln 1)x}y=e(ln1)xCy=e(ln2)xy=e^{(\ln 2)x}y=e(ln2)xDy=e(ln3)xy=e^{(\ln 3)x}y=e(ln3)xCheck Show answer Walk through it step by step Practice more like this Review this concept