TrigonometryHardTrigonometric Equations ShareTrigonometric Equations · Hard problemFind the sum of all solutions of sin(x+π3)+sin(x−π3)=sin2x\sin\left(x + \dfrac{\pi}{3}\right) + \sin\left(x - \dfrac{\pi}{3}\right) = \sin 2xsin(x+3π)+sin(x−3π)=sin2x in the interval [0,2π)[0, 2\pi)[0,2π).Check Show answer Walk through it step by step Practice more like this Review this concept