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TrigonometryHardTrigonometric Equations

Trigonometric Equations · Hard problem

Find the sum of all solutions of 2sin⁡2x−5sin⁡xcos⁡x+2cos⁡2x=02\sin^2 x - 5\sin x\cos x + 2\cos^2 x = 0 in the interval [0,2π)[0, 2\pi).

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