PrecalculusSuperchallengeTriangle Trigonometry and Vectors ShareTriangle Trigonometry and Vectors · Superchallenge problemIn △ABC\triangle ABC△ABC, ∠B=60∘\angle B=60^\circ∠B=60∘ and b=CA=3b=CA=\sqrt3b=CA=3. Find the largest possible value of a+2ca+2ca+2c, where a=BCa=BCa=BC and c=ABc=ABc=AB.Check Show answer Walk through it step by step Practice more like this Review this concept