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CalculusEasyThe Derivative

The Derivative · Easy problem

A trough fills so its depth is y=tt+1y=\dfrac{t}{t+1} meters (tt in hours, t≥0t\ge0). Its filling rate at t=0t=0 is y′(0)y'(0). At what later time tt has the filling rate dropped to ONE QUARTER of that initial rate?

A trough fills so its depth is y=t/t+1 meters (t in hours, t… — The Derivative · Easy problem | MathCastle