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Statistics & DataEasyRandom Variables

Random Variables · Easy problem

A random variable XX has P(X=0)=14P(X = 0) = \dfrac14, P(X=1)=12P(X = 1) = \dfrac12 and P(X=2)=14P(X = 2) = \dfrac14. Find Var(X)\mathrm{Var}(X). Express your answer as a common fraction.