PrecalculusSuperchallengeSequences, Series, and the Binomial Theorem ShareSequences, Series, and the Binomial Theorem · Superchallenge problemEvaluate ∑k=1201k(k+1)(k+2)=11⋅2⋅3+12⋅3⋅4+⋯+120⋅21⋅22\displaystyle\sum_{k=1}^{20}\frac{1}{k(k+1)(k+2)} = \frac{1}{1\cdot2\cdot3} + \frac{1}{2\cdot3\cdot4} + \cdots + \frac{1}{20\cdot21\cdot22}k=1∑20k(k+1)(k+2)1=1⋅2⋅31+2⋅3⋅41+⋯+20⋅21⋅221.Check Show answer Walk through it step by step Practice more like this Review this concept